2x^2+30x-9775=0

Solution for 2x^2+30x-9775=0 equation:

2x^2+30x-9775=0

a = 2; b = 30; c = -9775;
Δ = b2-4ac
Δ = 302-4·2·(-9775)
Δ = 79100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{79100}=\sqrt{100*791}=\sqrt{100}*\sqrt{791}=10\sqrt{791}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-10\sqrt{791}}{2*2}=\frac{-30-10\sqrt{791}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+10\sqrt{791}}{2*2}=\frac{-30+10\sqrt{791}}{4}
$